Mercurial > repos > metexplore > met4j

annotate findToolsWithoutTests.py @ 8:1274e2a62479 draft default tip

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planemo upload for repository https://forgemia.inra.fr/metexplore/met4j-galaxy commit e34acf0f51cafcf6ae7c97b4feb3188a39f17c32
author metexplore
date Wed, 26 Jul 2023 15:33:45 +0000
parents 7a6f2380fc1d
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6
7a6f2380fc1d planemo upload for repository https://forgemia.inra.fr/metexplore/met4j-galaxy
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1 import os
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2 import xml.etree.ElementTree as ET
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3
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4 def find_xml_files_without_tests(directory):
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5 for filename in os.listdir(directory):
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6 filepath = os.path.join(directory, filename)
7a6f2380fc1d planemo upload for repository https://forgemia.inra.fr/metexplore/met4j-galaxy
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7 if os.path.isdir(filepath):
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8 # Récursivement, recherche dans les sous-répertoires
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9 yield from find_xml_files_without_tests(filepath)
7a6f2380fc1d planemo upload for repository https://forgemia.inra.fr/metexplore/met4j-galaxy
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10 elif filename.endswith(".xml"):
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11 # Traitement du fichier XML
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12 tree = ET.parse(filepath)
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13 root = tree.getroot()
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14 tool_elements = root.findall(".//tool")
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15 tests_elements = root.findall(".//tests")
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16 if tool_elements and not tests_elements:
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17 yield filepath
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18 elif tests_elements:
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19 # On vérifie qu'il n'y a rien à l'intérieur de <tests>
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20 tests_children = list(tests_elements[0])
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21 if len(tests_children) == 0:
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22 yield filepath
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23
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24 if __name__ == "__main__":
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25 import argparse
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26 parser = argparse.ArgumentParser(description="Trouve les fichiers XML sans élément <tests>")
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27 parser.add_argument("directory", metavar="DIRECTORY", type=str, help="Le répertoire à explorer")
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28 args = parser.parse_args()
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29
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30 for filepath in find_xml_files_without_tests(args.directory):
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31 print(filepath)